Question

in triunghiul ABC m(A)=90 si se stie ca inaltimea AD =12 cm si DB/BC = 9/16 determinati perimetrul triunghiului

Answer 1

teorema inaltimii
AD²=DB*BC
DB/BC=9/16
9*16=144
AD²=12²=144
BC=9+16=25
AB=√(12²+9²)=√(144+81)=√225=15 cm
AC=√(12²+16²)=√(144+256)=√400=20 cm
P=15+20+25=60 cm