Question

In triunghiul DEF cu D= 90 gr , construim mediana DM si inaltimea DN. Daca DM=15 cm si DN =10 cm , aflati aria DEF

Answer 1

ΔDEF- dreptunghic |
DM- mediana          | ⇒ $DM= \frac{EF}{2}$ => DM=EM=MF=15 cm=> 
DM= 15 cm             |


=> EF= 30 cm

$A_{tr.dr} = \frac{h*ip}{2}= \frac{10*30}{2}= \frac{300}{2}= 150cm^{2}$