Question

Inecuatie partea intreaga:

[ a+ 1/2]=(5a-1)/3

Answer 1

[a+1/2]=k ∈Z=>
k=(5a-1)/3
3k=5a-1
a=(3k+1)/5
[3k+1/5+1/2]=k
[30k+(2+5)/1o]=k
[30k+7/10]=k
30k  este  un  numar  intre,Iese  in  afara  parantezei
30k+[7/10]=k
[7/10]=-29 k=.
0=- 29k
k=0
(5a-1)/3=0 
a=1/5