Question

Intr-o incapere se afla 2 gaze . Calculati
masa molara a amestecului :
a. Azot N1= 12×10^23
Oxigen N2=4×10^23

Answer 1

[tex]\text{Se calculeaza masele molare:}\\ \mu_{N_2}=2\cdot A_N=28\ g/mol\\ \mu_{O_2}=2\cdot A_O=32\ g/mol\\ \text{Se aplica formula:} \dfrac{m}{\mu}=\dfrac{N}{N_A}\Rightarrow m=\frac{N\cdot \mu}{N_A}\\ \text{Pentru azot:}m_{N_2}=\dfrac{N_1\cdot \mu_{N_2}}{N_A}=calcule=56 g\\ \text{Pentru oxigen:}m_{O_2}=\dfrac{N_2\cdot \mu_{O_2}}{N_A}=calcule=21,3 g\\ Apoi:\\ \nu=\nu_1+\nu_2\\ \dfrac{m_{O_2}+m_{N_2}}{\mu}=\dfrac{m_{O_2}}{\mu_{O_2}}+\dfrac{m_{N_2}}{\mu_{N_2}}\\ \text{Si de aici afli}\ \mu -ul.[/tex]