Question

Intr-o progresie aritmetica cu ratia 4,avem $a_{6}$= -13.Calculati $a_{10}$.Ajutati-ma!

Answer 1

r=4
a6=a1+5r=a1+20=-13
a1=-33
a10=a1+9r=-33+36=3

Answer 2

r=4
a6=a1+5r=a1+20=-13
a1=-33
a10=a1+9r=-33+36=3
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