Question

Intr-un cos erau mere si pere, in total 23 de fructe. mere erau cu 5 mai putine decat prune. cate mere erau in cos? cu schema

Answer 1

x-numarul merelor
x+5-numarul perelor
x+x+5=23
2x+5=23
2x=23-5
2x=18
x=18/2
x=9 mere
x+5 nr perelor =>9+5=14-pere
V:9+14=23
Sper ca te-am ajutat..

Answer 2

m + p = 23 (fructe)
m = p - 5 ==> p = m + 5
m /-----/
p /-----/+5
23 - 5 = 18
18 : 2 = 9 (un segment egal)
m = 9 mere
p = 9 + 5 = 14 pere

verificare:
9 + 14 = 23
9 = 14 -5
9 = 9