Question

introduceti intregii in fractie, calculati, si unde este posibil, simplificati si scoateti intregii, din fractis rezultata​
D au coroana

Answer 1

Răspuns.

Explicație pas cu pas:

a)  

3 intregi si 1 / 5 = ( 3 × 5 + 1 ) / 5 = 16 / 5

8 intregi si 3 / 4 = ( 8 × 4 + 3 ) / 4 = 35 / 4

= ( 16 / 5 ) × ( 35 / 4 ) = 4 × 7 = 28

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b)  

1 intreg si 2 / 7 = ( 1 × 7 + 2 ) / 7 = 9 / 7

1 intreg si 13 / 15 = ( 1 × 15 + 13 ) / 15 = 28 / 15

= ( 9 / 7 ) × ( 28 / 15 ) = ( 28 / 7 ) × ( 9 / 15 ) = 4 × ( 3 / 5 ) =

=  12 / 5 = 2 intregi si 2 / 5

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c)  

5 intregi si 5 / 8 = ( 5 × 8 + 5 ) / 8 = 45 / 8

1 intreg si 7 / 25 = ( 1 × 25 + 7 ) / 25 = 32 / 25

= ( 45 / 8 ) × ( 32 / 25 ) = ( 45 / 25 ) × ( 32 / 8 ) =

= ( 9 / 5 ) × 4 = 36 / 5 = 7 intregi si 1 / 5

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d)

3 intregi si 3 / 13 = ( 3 × 13 + 3 ) / 13 = 42 / 13

2 intregi si 11 / 14 = ( 2 × 14 + 11 ) / 14 = 39 / 14

= ( 42 / 13 ) × ( 39 / 14 ) =

= ( 42 / 14 ) × ( 39 / 13 ) =

= 3 × 3 =

= 9