Question

Introduceți sub radical 12√2 ; 4√3 ; 3√3 ; -2√2 ; -6√7 ; 1,5√7.
calculați:
√300
√3x la 2

Answer 1

a)
$12\sqrt{2}=\sqrt{144}\sqrt{2}=\sqrt{288} \\ \\ 4\sqrt{3}=\sqrt{16}\sqrt{3}=\sqrt{48} \\ \\ 3\sqrt{3}=\sqrt{9}\sqrt{3}=\sqrt{27} \\ \\ -2\sqrt{2}=-\sqrt{4}\sqrt{2}=-\sqrt{8} \\ \\ -6\sqrt{7}=-\sqrt{36}\sqrt{7}=\sqrt{252} \\ \\ 1,5\sqrt{7}=\sqrt{2,25}\sqrt{7}=\sqrt{15,75}$
b)
$\sqrt{300}=\sqrt{100}\sqrt{3}=10\sqrt{3} \\ \\ \sqrt{3x^2}=\sqrt{x^2}\sqrt{3}=|x|\sqrt{3}$