Question

un biciclist a parcurs in 3 zile un traseu cu lungimea de 108 km in a doua zi a parcurs 6 km mai mult decat in prima zi iar in a 3 zi a parcurs cu 6 km ma mult decat in a 2 zi .Calculati distanta parcursa in prima zi

Answer 1

prima zi=x
a doua zi=y
a treia zi=z
y=6+x
z=6+y=6+6+x=12+x
x+y+z=108=>x+6+x+12+x=108=>3x=90=>x=90/3=>x=30

Answer 2

x+(x+6)+(x+12)=108

3x=90

x=30km in prima zi

x+6=36 km in a doua zi

x+12 = 42 km in a treia zi