Question

La 40 va rog frumos cum aflu compusul B, C si A mi-a dat metan si pentina

Answer 1

cxh2x+2 + 3x+1)/2 = x co2 + x+1 h2o
cyh2y + 3y/2 o2 = y co2 + y h2o
czh2z-2 + 3z-1)/2 = z co2 + z-1 h2o
mC/mH = 12x/2x+2 = 3/1 => 6x+6=12x=>6x=6=>x=1=> A: CH4 - metan
CH4 + 2O2 = CO2 + 2H2O
1 mol CH4........1 mol CO2
a moli CH4........a' moli CO2
a' = a
1 mol czh2y............y moli co2
b moli czh2y...........b' moli co2
b' = b*y
nr atomi H alchina = 2*4 = 8 => 2x-2=8=2x=10=> x=5 => C: C5H8 - pentina
C5H8 + 7 O2 = 5 CO2 + 4 H2O
1 mol C5H8.........5 moli CO2
c moli C5H8...........c' moli CO2
c' = 5c
a'+b'+c'=44 (985,6/22,4) => a+by+5c=44
masa alcan = nr moli alcan * masa molara => nr moli alcan = 16/16 => a = 1 mmol
a/b = 1/3 => b=3a => b = 3*1 = 3 mmoli 
a/c = 1/5 => c=5a => c = 5*1 = 5 mmoli
1+3*3*y+5*5=44=>3y=18=> y = 6 => B: C6H12 - hexena