Question

La chimie, dau 100 de punctee​

Answer 1

I.

Z=21

a. 1s2 2s2 2p6 3s2 3p6 4s2 3d1

b. grupa III-B, per. 3

c. blocul d

Y, cu 4e- in 4p

a. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4

b. grupa VI-A, per. 4

c. blocul p

Z, 1e- lipsa pe 5s

a.  1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1

b. grupa I-A, per. 5

c. blocul s

II.

2. orbital

3. 2

4. maxim

III.

1. 14p+ => 14e- => 1s2 2s2 2p6 3s2 3p2

=> gr. IV-A, per. 3 => b)

2. gr. II-A = 2e- pe ultimul strat

per. 3 = stratul in care se termina config = 3

=> 3s2

=> 1s2 2s2 2p6 3s2 => Z = 2+2+6+2 = 12

=> b)

IV.

1-c, d

2-a

3-b

4-e

V.

a. 3s2

=> 1s2 2s2 2p6 3s2, Z=2+2+6+2 = 12

gr. II-A, per. 3

b. 4p5

=> 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5, Z=2+2+6+2+6+2+10+5 = 35

gr. VII-A, per. 5

c. 3d5-3 = 3d2

=> 1s2 2s2 2p6 3s2 3p6 4s2 3d2, Z=2+2+6+2+6+2+2 = 22

gr. IV-B, per. 4

d. 3p6-2 = 3p4

=> 1s2 2s2 2p6 3s2 3p4, Z=2+2+6+2+4 = 16

gr. VI-A, per. 3