Question

la ex 18 19.. repedeeee

Answer 1

18) A={2,3,4,5,6}
B={1,2} deoarece
y=(2+1)/3=1; (3+1)/3=4/3=1,3333333 nu apartin lui N; 5/3;7/3
6/3=2
AUB={1,2,3,4,5,6} elemente care se gasesc si in A,dar si in B
A∩B={2}
A¬B={3,4,5,6}
B- A={1}

19) A={2,3,12,102,103,1002,1003}
       B={1,2,11,101,102,1001,1002}
       C={3,4,13,103,104,1003,1004}
   B∪C={1,2,3,4,11,13,101,102,103,104,1001,1002,1003,1004}