Question

La presiunea de 2 atm si temperatura de 25 grade celsius un gaz X cu masa 1,5845 ocupa un volum de 440 cm cubi.Masa a 2L de gaz in conditii normale este:

Answer 1

pV=m/M*R*T => M=m*R*T/p*V = 1,5845*82*298*10^(-3)/2*0,44 = 44g/mol [CO2]

p*V=m/M*R*T => m=p*V*M/RT = 1*2*44/0,082*273 = 3.931g CO2

Answer 2

P×V= nr. moli × R × T
T= 25+273= 298
V= 440/1000=0,44 l
2×0,44= nr. moli ×0.082× 298
Nr.moli=0.036
masa moleculara=1,5845/0.036=44
Gazul este CO2
1×2=nr. moli×0,082×273
Nr. moli = 0.089
Masa= 0.089×44= 4
Sper ca e ok. Bafta!