Question

La un test de evaluare dat celor 51 de elevi de la doua clase, numarul elevilor care au obtinut cele cinci tipuri de punctaje : x, y, z, t, s corespunde procentelor : 41,17% ; 23,53% ; 17,64% ; 11,76% ; 5,88% .
Se stie ca 8,99 < x ; 8,00 ≤ y <9 ; 7,00 ≤ z < 8 ; 5 < t < 7 ; 4,00 ≤ s < 5
a) Aflati numarul elevilor corespunzator fiecaruia din cele 5 punctaje
b) Intre ce limite este cuprinsa media obtinuta la acest test?

Answer 1

51 × 41,17%= 21 elevi
51 × 23,53%= 12 elevi
51 × 17,64%= 9 elevi
51 × 11,76%= 6 elevi
51 × 5,88%= 3 elevi

8,99 < x ; 8,00 ≤ y <9 ; 7,00 ≤ z < 8 ; 5 < t < 7 ; 4,00 ≤ s < 5
(21×8,99+12×8+9×7+9×5+3×4)/51=7,93
(21×8,99+12×9+9×8+9×7+3×5)/51=8,76
7,93< media test <8,76