Question

lo[tex] log_{3} 2 = a
[/tex] Aratati ca [tex] log_{3}8 + log_{3}100 - log_{3}25 = 5a
[/tex]

Answer 1

$= log_{3}( \frac{8*100}{25})= log_{3} 32= log_{3} 2^{5}=5 log_{3}2 =5a$

Answer 2

log38+log3100-log325=5a
log3800-log325=log3800/25=
log332
log3din2∧5
5log3din
adevarat
succes