Question

log in baza 2 din 1/4 minus radical de ordin 3 din minus 8

Answer 1

$\log_2\frac{1}{4} - \sqrt[3]{-8} = \log_24^{-1} - \sqrt[3]{(-2)^3} = \log_22^{-2} + 2 = -2 + 2 = 0.$