Question

log$log_{x} \frac{1}{8} = \frac{3}{2}$
si
$log _{4 \sqrt[3]{4} }x= -\frac{3}{4}$

Answer 1

[tex]1.\ ...\Leftrightarrow x^\frac{3}{2}=\frac{1}{8}\Leftrightarrow x=(\frac{1}{8})^\frac{2}{3}=\sqrt[3]{(\frac{1}{8})^2}=(\frac{1}{2})^2=\frac{1}{4}\\ 2.\ ...\Leftrightarrow x=(4\sqrt[3]4)^{-\frac{3}{4}}=4^{(1+\frac{1}{3})}^{(-\frac{3}{4})}=4^{-1}=\frac{1}{4} [/tex]