Question

log6 (4x-8)=1 rezolvarea la acest exercitiu​

Answer 1

 

$\displaystyle\bf\\log_{_{\b6}}(4x-8)=1\\\\4x-8=6^1\\\\4x-8=6\\\\4x=6+8\\\\4x=14\\\\x=\frac{14}{4}\\\\x=\frac{7}{2}\\\\\boxed{\bf x=3,\!5}$