Question

Ma ajuta cineva???ex.19

Answer 1

a) (2 √5²x3³-5 √2⁶x3) : (2√5²)=
=(2x5x3√3-5x2³√3) : (2x5)=
=(30√3-40√3) : 10=
=(-10√3) : 10=
= - √3

b) ( √5³-√5x9²) : √5 - ( √2x7x9² - √2x3x10²)=
=(5√5 - 9√5):√5 - ( 9√14 -10√6)=
=(-4√5)x 1/√5-9√14+10√6=
=10√6-9√14-4

c)(
( √2x3x11² + √2⁵x3³) : √6 - √6( √2³x3³- √2x3x10²)=
=(11√6 + 12√6): √6 - √6 ( 6√6 - 10 √6)=
=23√6 x 1/√6 - √6 x (-4 √6)=
=23 +4x6=
=23+24
= 47

d) √5 x ( √ 5 x 17² - √ 5 x13²) + ( √ 2² x5 x 9² - √ 5 x 19²) : √5=
=√5 ( 17√5 -13√5) + ( 18√5 -19√5 ) :√5=
=√5 x 4 √5 + (- √5) x 1 /√5=
=4 x 5 -1=
=20-1=
=19

e) 
(√9²x11 - √11x 13²) : (2√11) - ( √7² x 13 + √5²x13) : √13=
=(9√11-13√11):2√11- (7√13 +5√13) : √13=
=(-2√11) x 1 /2 √11  - 12 √13 x 1 /√13 =
=-1 - 12=
= - 13

f
(√3³x5² + √ 2²x3x10²) : √3x5² + ( √7x11² -√2²x7x9²): √7=
=( 15 √3 + 20√3) : 5√3 + ( 11√7 - 18√7) : √7=
=35 √3 x 1 /5 √3 + (-7√7):√7=
=7 -7=
=0