Question

Ma ajuta ti cu rezilvarea:
[(3^16+3^17):3^14-2^2]^3

Answer 1

[(3^16+3^17):3^14-2^2]^3 =

[ 3^16 x (1 + 3) : 3^14 - 4 ]^3 =

[ 3^16 x 4 : 3^14 - 4 ]^3 =

[3^(16-14) x 4 - 4]^3 =

[3^2 x 4 - 4]^3 =

[ 9 x 4 - 4]^3 =

[36 - 4]^3 =

32^3 =

32768

Answer 2

[ ( 3¹⁶ + 3¹⁷ ) : 3¹⁴ - 2² ]³ = 32 768

= [ ( 3² + 3³ ) x 3¹⁴ : 3¹⁴ - 4 ]³ =

= [ ( 9 + 27 ) - 4 ]³ =

= ( 36 - 4 )³ =

= 32³ =

= 32 768