Question

ma ajutati va roggggggggggg, dau coroana​

Answer 1

$2\frac{3}{4}*(6\frac{2}{33} -2\frac{4}{11}):7\frac{5}{8}=\\\\\\\frac{2*4+3}{4} *(\frac{6*33+2}{33}-\frac{2*11+4}{11}):\frac{7*8+5}{8}=\\\\\frac{8+3}{4}*(\frac{198+2}{33}-\frac{22+4}{11}):\frac{56+5}{8}=\\\\\frac{11}{4}*(\frac{200}{33}-\frac{26}{11}):\frac{61}{8}=\\\\\\\\\frac{11}{4}*(\frac{200-78}{33}) :\frac{61}{8}=\\ (am facut 26*3)\\\\\frac{11}{4}*\frac{122}{33}*\frac{8}{61}=\\\\\\11*\frac{2}{33}*8= \frac{2}{3}*2=\frac{4}{3}$