Question

Mă poate ajuta cineva ?

Answer 1

Bună! Răspunsul este mai jos.

$0.(3) \times 12 \sqrt{8} - ( \frac{5}{ \sqrt{2} } + \frac{21}{ \sqrt{18} } - \frac{99}{ \sqrt{242} } ) \div 0.5$

$\frac{3}{9} \times 12 \sqrt{8} - ( \frac{5}{ \sqrt{2} } + \frac{21}{ \sqrt{18} } - \frac{99}{ \sqrt{242} } ) \div \frac{5}{10}$

$\frac{1}{3} \times 12 \times 2 \sqrt{2} - ( \frac{5}{ \sqrt{2} } + \frac{21}{ 3\sqrt{2} } - \frac{99}{ 11\sqrt{2} } ) \times \frac{10}{5}$

$4 \times 2 \sqrt{2} - ( \frac{5}{ \sqrt{2} } + \frac{7}{ \sqrt{2} } - \frac{9}{ \sqrt{2} } ) \times 2$

$8 \sqrt{2} - ( \frac{5}{ \sqrt{2} } + \frac{7}{ \sqrt{2} } - \frac{9}{ \sqrt{2} } ) \times 2$

$8 \sqrt{2} - \frac{3}{ \sqrt{2} } \times 2$

$8 \sqrt{2} - \frac{6}{ \sqrt{2} }$

$8 \sqrt{2} - 3 \sqrt{2} = 5 \sqrt{2}$