Question

ma poate ajuta cineva va rog

Answer 1

Răspuns:

1. F:R->R, f(x) = - 3x+3

a) f(-1)= - 3(-1)+3 => 3+3 => 6.

f(2)= - 3*2+3= - 6+3= - 3.

b) f(-3)= - 3(-3)+3= 9+3= 12

f(-2)= - 3(-2)+3= 6+3=9

f(1)= -3+3= 0

f(3)= - 3*3+3= -9+3= - 6

F(-3)+f(-2)+f(-1)+f(1)+f(2)+f(3)= 12+9+6+0-3-6= 27-3-6= 24-6= 18