Question

Ma puteti ajuta?....

Answer 1

$\frac{X+1+3X+1}{2X+1} = \frac{4X+2}{2X+2} = \frac{2X+1}{X+1} = 2$

$\frac{3A+2B+2A+3B}{A+B} = \frac{5A+5B}{A+B} = \frac{5(A+B)}{A+B} =5$

$\frac{100A+10B+C+100C+10A+B+100B+10C+A}{999} = \frac{111A+111B+111C}{999} = \frac{111(A+B+C)}{999}$

$\frac{5A+3-3A+1}{3A+6} = \frac{2A+4}{3A+6}$

Atât te-am putut ajuta