Question

Ma puteti ajuta?
(√5-3)²;
(√2+√7)²;
(√3+5)²;
(3-√7)²;
(2√2-1)²;
(5-√2)²;
(√6-√3)²;
(9-√2)²;
(√7-√5)²;
(7+√5)²;
(3√2-1)²;
(3-√2)²;
(7+2√2)².
Nu am pretentia de a fi toate rezolvate,macar o parte. Multumesc anticipat! ^_^

Answer 1

 5-6√5+9=14-6√5=2(7-3√5)
2+2√14+7=9+2√14
3+10√3+25=28+10√3
9-6√7+7=16-6√7=2(8-3√7)
8-4√2+1=9-4√2
25-10√2+2=27-10√2

foloseste formulele
(a+b)²=a²+2ab+b²
(a-b)²=a²-2ab+b

Answer 2

de regula poti folosi formule de calcul prescutat
(a+b)²=a²+2ab+b²
(a-b)²=a²-2ab+b²
(√5-3)²=(√5)²-2×√5×3+3²=5-6√5+9=14-6√5
(√2+√7)²=(√2)²+2×√2×√7+(√7)²=2+2√14+7=9+2√14
(√3+5)²=(√3)²+2×√3×5+5²=3+10√3+25=28+10√3
(3-√7)²=3²-2×3×√7+(√7)²=9-6√7+7=16-6√7
(2√2-1)²=(2√2)²-2×2√2×1+1²=8-4√2+1=9-4√2