Question

ma puteti ajuta la amandouaaa va rog frumos

Answer 1

Ce exercitiu mai exact?

Answer 2

3.a) = (12$x^{2}$-15x-4x-5)-(12$x^{2}$+30x-22x-55)=
12$x^{2}$-11x-5 -12$x^{2}$-8x+55= 50 -18x
b) = 2x[4$x^{2}$-($x^{2}$-3x+2x-6)] -5$x^{3}$+15x=
2x(4$x^{2}$-$x^{2}$+x+6 ) -5$x^{3}$+15x =
6$x^{3}$+2$x^{2}$+12x-5$x^{3}$+15x = $x^{3} +2 x^{2}$+27x =x($x^{2}$$+2x+27)$
c) = (x+1)(3x+6-2x+2)-4x-8= (x+1) ( x+8) -4x-8 = $x^{2}$+8x+x+8 -4x-8 =
$x^{2}$+4x = x(x+4)
d) =(x-2)(4x+20 -3x -18)-$x^{2}$+4x =(x-2)(x+2) -$x^{2}$+4x = $x^{2} +2x-2x-4- x^{2} +4x=4x-4=4(x-1)$
4a) = 8$x^{3} -12 x^{2} -12x+4-2 x^{3} +6 x^{2} -8x-20 x^{3} +30 x^{2} -30x = -14 x^{3} +$$24 x^{2} -50x+4$
la 4 B se vede neclar si nu pot rezolva