Question

ma puteți ajuta va rog?​

Answer 1

Răspuns:

a) B=2×A+I2

$2 \times \binom{1 \: 1}{1 \: - 1} + \binom{1 \: 0}{0 \: 1}$

$\binom{2 \: 2}{2 \: - 2} + \binom{1 \: 0}{0\: 1}$

$\binom{3 \: 2}{3 \: - 1}$

c) x×I2+2A=

$\binom{4 \: 2}{2 \: 0}$

$x \times \binom{1 \: 0}{0 \: 1} + 2 \times \binom{1 \: 1}{1 \: - 1} = \binom{4 \: 2}{2 \: 0}$

$\binom{x \: 0}{0 \: x} + \binom{2 \: 2}{2 \: - 2} = \binom{4 \: 2}{2 \: 0}$

$\binom{x + 2 \: 2}{2 \: x - 2} = \binom{4 \: 2}{2 \: 0}$

x+2=4---->x=2

2=2

2=2

x-2=0---->x=2