Question

Ma puteti ajuta va rog frumos la expresia : E (x)= (2 supra x - 1 - 1 supra x + 1) : (x+3)(x-1) totul supra x^2 -2x + 1. arătați ca E (x) = 1 supra x + 1 Va rooog mult de tot

Answer 1

$E(x)=( \frac{2}{x-1} - \frac{1}{x+1} ): \frac{(x+3)(x-1)}{x ^{2}-2x+1 }$

Se,aduce,la,numitor,comun,in,paranteza(x-1)(x+1)

$E(x)= \frac{2x+2-x+1}{(x -1)(x+1) } * \frac{(x-1) ^{2} }{(x+3)(x-1)}$

$E(x)= \frac{x+3}{(x-1)(x+1)} * \frac{(x-1) ^{2} }{(x+3)(x-1)} = \frac{1}{x+1}$