Question

Masa unui cub cu latura de 10 cm ce produce o alungire de 50 mm, constanta elastica a resortului k=200N/m, g=10N/Kg

Answer 1

∆l=50 mm=0,05 m V=l^3=10^3=1000 cm^3=0,001 m^3 Fel=k∆l=200•0,05 =10 N Fel=G=mg=>m=G/g=10/10=1 kg