Question

Media aritmetica a 12 numere rationale pozitive dau coroana

Answer 1

$Fie~numerele~a_{1}<a_{2}<...<a_{12}$
$\frac{a_{1}+a_{2}+...+a_{12}}{12}=47,2$
$a_{1}+a_{2}+...+a_{12}=566,4$
$\frac{a_{1}+a_{12}}{2}=49,5$
$a_{1}+a_{12}=99$
$a_{2}+a_{3}+...+a_{11}=566,4-99=467,4$
$\frac{a_{2}+a_{3}+...+a_{11}}{10}=\frac{467,4}{10}=46,74$