Question

media geometrica a numerelor 12√3,288,108√9​

Answer 1

$\it m_g=\sqrt[3]{12\sqrt3\cdot288\cdot108\sqrt9}=\sqrt[3]{12\cdot288\cdot108\cdot3\sqrt3}=\\ \\ \\ =\sqrt[3]{12\cdot144\cdot2\cdot4\cdot3\cdot9\cdot3\sqrt3}=\sqrt[3]{12\cdot12^2\8\cdot27\cdot3\sqrt3}=12\cdot2\cdot3\sqrt[3]{3\sqrt3}$