Question

Media geometrica a numerelor a=|2v3-3v2| si b=v12+v18

Answer 1

a= |2v3-3v2| = -2v3+3v2
b= v12 +v18
v12= 2v3
v18 = 3v2 => b=2v3 + 3v2

Mg = $\sqrt{ a x b}$
Mg = $\sqrt{-2v3+3v2  x 2v3 + 3v2}$
  

Answer 2

 [tex] a=|2\sqrt3-3\sqrt2|=|\sqrt{2^2\cdot3}-\sqrt{3^2\cdot2}|=|\sqrt{12}-\sqrt18}|<0\\ \Rightarrow\;\;a=-(\sqrt12-\sqrt18)=\sqrt{18}-\sqrt{12}\surd\surd\\ \Rightarrow\;\;m_g=\sqrt{\underbrace{(\sqrt18-\sqrt12)(\sqrt18+\sqrt12)}_{formula\;a^2-b^2\,!}}=\sqrt{18-12}=\sqrt6\;[/tex]