Question

media geometrică a numerelor reale 3√21 si 7√21

Answer 1

$\it a=3\sqrt{21},\ \ \ \ b=7\sqrt{21}\\ \\ m_g=\sqrt{a\cdot b} =\sqrt{3\sqrt{21}\cdot7\sqrt{21}}=\sqrt{3\cdot7\cdot\sqrt{21}\cdot\sqrt{21}}=\sqrt{21\cdot21}=\\ \\ =\sqrt{21^2}=21$