Question

Mircea, Andrei, Catalin si Narcisa au impreuna 1140 de timbre. Cate timbre are fiecare daca Narcisa are cu 40 de timbre mai mult decat Andrei si Catalina la un loc, Catalina are cu 80 de timbre mai putin decat Andrei, iar Mircea are de trei ori mai multe decat Andrei?

PRIMUL RASPUNS CORECT ARE MULTUMESC + COROANA

Answer 1

M + A + C + N = 1 140 timbre
N = A + C + 40
C = A -80 => A = C +80
M = 3×A
M |___|___|___|+240
A |___|+80
C |___|
N |___|___|+40+80
avem 7 segmente egale +240 + 80 + 40 + 80 = 1 140
1 140 - (240+80+40+80) = 1 140 - 440 = 700
700 : 7 = 100 ( un segment egal)
M = 3×100 + 240 = 300+240 = 540
A = 100+80 = 180
C = 100
N = 2×100+40+80 = 200+120 = 320

Verificare:
540 + 180 + 100 + 320 = 1 140

540 timbre are Mircea
180 timbre are Andrei
100 timbre are Catalin
320 timbre are Narcisa