Question

ms = 400 g HCl.
c = 36,5 .
ACl = 35,5.
Sa se afla n CH4= ?
Stiind formulele .
C+2H2-->CH4.
Zn+2HCl-->H2+Zn+Cl2.

Answer 1

c=md*100/ms
md = c*ms/100=36.5*400/100=146 g HCl
n=m/M=146/36.5=4 moli HCl

Zn+2HCl→H₂+Zn+Cl₂
2 moli HCl.......1 mol H₂
4 moli HCl.......x
x=4/2=2 moli H₂

C+2H₂→CH₄
2 moli H₂........1 mol CH₄
2 moli H₂.......y                               y=2/2=1 mol CH₄