Question

Multimea solutiilor reale ale ecuatiei 2x-1 pe 12= 3 supra 2x-1. × diferit de 1 pe 2.

Answer 1

$\frac{2x-1}{12}= \frac{3}{2x-1}$
(2x-1)^2=36
4x^2-4x+1-36=0
4x^2-4x-35=0
Δ=16+560=576
x1=(4+√576)8=(4+24)/8=28/8=7/2
x2=(4-√576)/8=(4-24)/8=-20/8=-5/2