Question

Multumesc!!!!!!!!!!!!

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Answer 1

Răspuns:

Explicație pas cu pas:

(x^3 - 2x^2)/2x^2 = x^2(x - 2) / 2x^2 = (x - 2)/2

[(x - 2)/2  - (x- 2)(x + 2)/4x] : (x - 2)/2 =

(x - 2)/2 * 2 / (x - 2) - (x - 2)(x + 2)/4x * 2/(x - 2) =

1 - (x + 2)/2x = 1 - 1/2 - 1/x = 1/2 - 1/x

1/2 - 1/x + 1/2 = 1 + 1/x

Answer 2

E(x)=[(x^2(x-2)/2x^2-(x-2)(x+2)/4x]*2/(x-2)+1/2

E(x)=[(x-2)/2-(x-2)(x+2)/4x]*2/(x-2)+1/2

E(x)=2/(x-2)*(x-2)/2-(x-2)(x+2)/4x*2/(x-2)+1/2

E(x)=1-(x+2)/2x+1/2

E(x)=1-x/2x-2/2x+1/2

E(x)=1-1/2-1/x+1/2

E(x)=1-1/x