Question

n=1+1+2+2²+2³+....+2²⁰¹⁸ va roggg​

Answer 1

Răspuns:

Explicație pas cu pas:

S = 1 + 2 + 2^2 + 2^3 + ...+2^2018

2S = 2 + 2^2 + 2^3 + 2^4 + ...+2^2019

2S - S = S = 2 + 2^2 + 2^3 + 2^4 + ...+2^2019 - 1 - 2 - 2^2 - 2^3 - ...- 2^2018

S = 2^2019 - 1

n = 1 + 2^2019 - 1 = 2^2019

Answer 2

1+1=2
2+2=4=2^{2}
2^{2}+2^{2}=4+4=8=2^{3}
:
:
:
2^{2018}+2^{2018}=2^{2019}

=> n=2^{2019}