Question

n=200+2×(1...2...3+......199)=
vreau sa ma verific
100 puncte!​

Answer 1

Răspuns:

$n=200+2*(1+2+3+...+199)$

$=200+2*\frac{199*(199+1)}{2}$

$=200+2*\frac{199*200}{2}$

$=200+199*200$

$=200*(1+199)$

$=200*200$

$=200^2=(2*100)^2=2^2*100^2=4*10000=40000$