Question

nu bagati in seama cerinta cu nr nat nenule,DAU COROANA

Answer 1

Răspuns:

${1 }^{2} + {2}^{x } + {3}^{y } < 4$

REZOLVARE:

${1}^{2} + {2}^{1 } + {3}^{0} < 4$

$1 + 2 + 0 < 4$

$3 < 4$