Question

Nu iese deloc
Ce trebuie sa fac

Answer 1

$E(x) = \dfrac{1}{x-2} + \dfrac{1}{x+2} -\dfrac{4\ }{4-x^2} =\dfrac{1}{x-2} + \dfrac{1}{x+2} +\dfrac{4\ }{x^2 -4} = \\\;\\ =\dfrac{x+2+x-2+4}{(x-2)(x+2)} =\dfrac{2x+4}{(x-2)(x+2)} = \dfrac{2(x+2)}{(x-2)(x+2)} =\dfrac{2}{x-2}.$