Question

Nu imi iese deloc..Ajutor

Answer 1

n1 moli C6H5-CH3 + Cl2 ⇒ C6H5-CH2Cl + HCl
n2 moli C6H5-CH3 + 2Cl2 ⇒ C6H5-CHCl2 + 2HCl
n3 moli C6H5-CH3 + 3Cl2 ⇒ C6H5-CCl3 + 3 HCl
n4 moli  C6H5-CH3 nereactionat
n1/4 = n2/2 = n3/1 = n4/1  = K     n1 = 4k   n2 = 2k  n3 =n4 = k
nHCl = n1 + 2n2 + 3n3 = nNaOH = 5,5
solutia de NaOH : ms = 550g   c = 40% ⇒ md = 220g 
nNaOH = 220/40 = 5,5 moli 
4k + 4k + 3k = 5,5    11k = 5,5  k = 0,5  (n1 = 2 , n2 = 1, n3 = n4 = 0,5) 
n toluen = 4moli    m = 4·92 = 368g
Cu = n1·100/n = 200/4 = 50%
Ct = (n1 + n2 + n3)·100/n = 3,5·100/4 = 87,5%