Question

Numarul /3-2√2/+/3-2√3/ +2√2      
calculat este.................

Answer 1

$/3-2 \sqrt{2} /+/3-2 \sqrt{3} /+2 \sqrt{2} = \\ =3-2 \sqrt{2}+2 \sqrt{3}-3+2 \sqrt{2} = \\ =2 \sqrt{3} \\ deoarece: \\ 3= \sqrt{9}> \sqrt{8}= 2 \sqrt{2} \\ si \\ 3= \sqrt{9}< \sqrt{12}= 2 \sqrt{3}$