Question

numerele a si b sunt invers proporționale cu 2 si 3 iar 6a+9b=36

Answer 1

$\frac{a}{b} = \frac{2}{3}$ =>2a = 3b = k

2a = 3b = k
a=k/2
b=k/3
6a+9b=36
6k/2 + 9k/3 = 36
3k+3k =36
6k=36
k=36/6
k=6

=> a= 3 
      b=2

Answer 2

6a+9b=36
2a = 3b = >k
a = k/2
b = k/3
6k/2 + 9k/3 =36
3k + 3k=36
6k = 36
k = 36 : 6
k = 6
a = 6/2 = 3
b = 6/3 = 2