Question

Numerele asib sunt direct proportionale cu 3 si4 si 25% din b este cu 3mai micdecat 0,8(3)din a.Aflati numerele.

Answer 1

a,b) d.p (3,4)
a/3=b/4=k
a=3k
b=4k
25%b=0,8(3)a-3
1/4b=(83-8)/90a-3
1/4b=75/90a-3
1/4b=15/18a-3
1/4b=5/6a-3
1/4*4k=5/6*3k-3
k=5/2k-3
3=3k/2
k=2
a=6
b=8