Question

O bucata de sapun cantareste 80 de grame si conti ne 10% sulf. Sa se calculeze numarul neutronilor continut in nucleele atomilor de sulf.

Answer 1

10pe100 ori 80=8 g S
1 mol S=32 g
deci avem  0.25 moli S
1 mol S .......16 ori N a neutroni
0.25 moliS.....x neutroni
deci avem 24,088 neutroni

Answer 2

10% din 80g=10*80/100=8g S
1atom de S, are z=16 si A=32 =>n=16 adica 16n°
1mol.......32gS........16*Na neutroni
.................8gS.........x=?
x=8*16Na/32=4*Na=4*6,023*10²³ neutroni=24,092*10²³neutroni