Question

O glicerida formeaza prin hidroliza acid palmitic si acid stearic, in raport molar 2:1. Calculati masa de palmitat de sodiu care se obtine prin saponificarea gliceridei, daca se consuma in proces 200 ml solutie NaOH, de concentratie 0,25 moli/litru.

Answer 1

glicerida = dipalmito stearina 
glicerida + 3NaOH ⇒2CH3-(CH2)14-COONa + CH3-(CH2)16-COONa + 3H2O
solutia de NaOH : Vs = 0,2 l   cM = 0,25 mol/l ⇒ nNaOH = 0,05 moli 
n palmitat = 2nNaOH/3 = 0,1/3 moli      M = 278g/mol 
m = 0,1/3 ·278 = 9,266g