Question

O proba de 138 g etsanol se oxideaza bland.Stiind ca produsul obtinut formeaza prin tratare cu r fehling 214,5 g de precipitat rosu,cantitatea de alcool neoxidata este : b)69 g

Answer 1

46g...................................1mol
CH3-CH2-OH + [O] -> CH3-CH=O + H2O
y=?..................................1,5moli
1mol........................................................144g
CH3-CH=O + 2Cu(OH)2 -> CH3-COOH + Cu2O + H2O
x=?...................................................214,5g
x=214,5/144=1,5moli
y=1,5*46=69g alcool oxidat
138-69=69g alcool neoxidat