Question

O solutie care contine 0,365 g HCl in 100 mL solutie are pH-ul....(0/1). Calculati va rog

Answer 1

MHCl = 1 + 35.5 g/mol = 36.5 g/mol

=> 0.365 g HCl = 0.365/36.5 moli HCl = 0.01 moli

HCl -> $H ^{+} + Cl^{-}$

din 0.01 moli HCl ... 0.01 moli H+

CM= n/Vo= 0.01 moli / 0.1 L = 0.1 

pH = -log[CM] = -log(0.1) = 1 => pH = 1