Question

O solutie de NaOH de concentratie c= 8% este neutralizata de ms2=61,25g solutie H2SO4 cu concentratie c2=10%.care este masa solutiei de ms1=? de Naoh care a fost neutralizata

Answer 1

se da
m(sol H2SO4)=61,25g
W(NaOH)=8%
W(H2SO4)=10%
m(sol NaOH)-??
   rezolvare:
 W-?       0,06mol
2NaOH+H2SO4=Na2SO4+2H2O
2mol       1mol
1)Aflam masa H2SO4 dupa formula:
m(H2SO4)=W(H2SO4)×m(sol H2SO4) ÷100%=10%×61,25g ÷ 1000%=6,125
2)Aflam V niu(H2So4)=m(H2SO4)÷M=6,125g÷98g/mol=0,06mol
3)Aflam niu(NaOH)=0,06mol×2mol÷1mol=0,12mol
4)Aflam m(NaOH)=V niu(NaOH)×M=0,12mol×40g/mol=4,8g
5)m(solNaOH)=m(NaOH)×100%÷W omega(NaOH)=4,8g×100% ÷ 8%=480÷8=60g
     Raspuns:m(solNaOH)=60g
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